2(s-5)=2(s/5)

Solution for 2(s-5)=2(s/5) equation:

2(s-5)=2(s/5)

We move all terms to the left:

2(s-5)-(2(s/5))=0

We add all the numbers together, and all the variables

2(s-5)-(2(+s/5))=0

We multiply parentheses

2s-(2(+s/5))-10=0

We multiply all the terms by the denominator


2s*5))-(2(+s-10*5))=0

We add all the numbers together, and all the variables

2s*5))-(2(s-50))=0

We add all the numbers together, and all the variables

2s*5))-(2(s=0

Wy multiply elements

10s^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$s=\frac{-b}{2a}=\frac{0}{20}=0$