2(s1+3)=s1(4s-5

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Solution for 2(s1+3)=s1(4s-5 equation: 



2(s1+3)=s1(4s-5

We move all terms to the left:

2(s1+3)-(s1(4s-5)=0

We add all the numbers together, and all the variables

2(s+3)-(s1(4s-5)=0

We multiply parentheses

2s-(s1(4s-5)+6=0

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