2(t+-4)+4=2(2t+-5)

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Solution for 2(t+-4)+4=2(2t+-5) equation:



2(t+-4)+4=2(2t+-5)
We move all terms to the left:
2(t+-4)+4-(2(2t+-5))=0
We add all the numbers together, and all the variables
2(t-4)-(2(2t-5))+4=0
We multiply parentheses
2t-(2(2t-5))-8+4=0
We calculate terms in parentheses: -(2(2t-5)), so:
2(2t-5)
We multiply parentheses
4t-10
Back to the equation:
-(4t-10)
We add all the numbers together, and all the variables
2t-(4t-10)-4=0
We get rid of parentheses
2t-4t+10-4=0
We add all the numbers together, and all the variables
-2t+6=0
We move all terms containing t to the left, all other terms to the right
-2t=-6
t=-6/-2
t=+3

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