2(t+2)-2+2t=2t+2(t+1)

Solution for 2(t+2)-2+2t=2t+2(t+1) equation:

2(t+2)-2+2t=2t+2(t+1)

We move all terms to the left:

2(t+2)-2+2t-(2t+2(t+1))=0

We add all the numbers together, and all the variables

2t+2(t+2)-(2t+2(t+1))-2=0

We multiply parentheses

2t+2t-(2t+2(t+1))+4-2=0


We calculate terms in parentheses: -(2t+2(t+1)), so:

2t+2(t+1)

We multiply parentheses

2t+2t+2

We add all the numbers together, and all the variables

4t+2

Back to the equation:

-(4t+2)


We add all the numbers together, and all the variables

4t-(4t+2)+2=0

We get rid of parentheses

4t-4t-2+2=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0