2(t+3)+7(t-3)=5(t-1)

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Solution for 2(t+3)+7(t-3)=5(t-1) equation:



2(t+3)+7(t-3)=5(t-1)
We move all terms to the left:
2(t+3)+7(t-3)-(5(t-1))=0
We multiply parentheses
2t+7t-(5(t-1))+6-21=0
We calculate terms in parentheses: -(5(t-1)), so:
5(t-1)
We multiply parentheses
5t-5
Back to the equation:
-(5t-5)
We add all the numbers together, and all the variables
9t-(5t-5)-15=0
We get rid of parentheses
9t-5t+5-15=0
We add all the numbers together, and all the variables
4t-10=0
We move all terms containing t to the left, all other terms to the right
4t=10
t=10/4
t=2+1/2

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