2(t+3)-4(t+1)=

Solution for 2(t+3)-4(t+1)= equation:

Simplifying
2(t + 3) + -4(t + 1) = 0

Reorder the terms:
2(3 + t) + -4(t + 1) = 0
(3 * 2 + t * 2) + -4(t + 1) = 0
(6 + 2t) + -4(t + 1) = 0

Reorder the terms:
6 + 2t + -4(1 + t) = 0
6 + 2t + (1 * -4 + t * -4) = 0
6 + 2t + (-4 + -4t) = 0

Reorder the terms:
6 + -4 + 2t + -4t = 0

Combine like terms: 6 + -4 = 2
2 + 2t + -4t = 0

Combine like terms: 2t + -4t = -2t
2 + -2t = 0

Solving
2 + -2t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -2t = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -2t = 0 + -2
-2t = 0 + -2

Combine like terms: 0 + -2 = -2
-2t = -2

Divide each side by '-2'.
t = 1

Simplifying
t = 1