2(t-(2t+6)+1)=2(t+5)

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Solution for 2(t-(2t+6)+1)=2(t+5) equation: 



2(t-(2t+6)+1)=2(t+5)

We move all terms to the left:

2(t-(2t+6)+1)-(2(t+5))=0



We calculate terms in parentheses: -(2(t+5)), so:

2(t+5)

We multiply parentheses

2t+10

Back to the equation:

-(2t+10)



We get rid of parentheses

2(t-(2t+6)+1)-2t-10=0

We add all the numbers together, and all the variables

-2t+2(t-(2t+6)+1)-10=0

We move all terms containing t to the left, all other terms to the right

-2t+2(t-(2t+6)+1)=10

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