2(t-1)-3(2t-1)=11-7(4t+3)

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Solution for 2(t-1)-3(2t-1)=11-7(4t+3) equation:



2(t-1)-3(2t-1)=11-7(4t+3)
We move all terms to the left:
2(t-1)-3(2t-1)-(11-7(4t+3))=0
We multiply parentheses
2t-6t-(11-7(4t+3))-2+3=0
We calculate terms in parentheses: -(11-7(4t+3)), so:
11-7(4t+3)
determiningTheFunctionDomain -7(4t+3)+11
We multiply parentheses
-28t-21+11
We add all the numbers together, and all the variables
-28t-10
Back to the equation:
-(-28t-10)
We add all the numbers together, and all the variables
-4t-(-28t-10)+1=0
We get rid of parentheses
-4t+28t+10+1=0
We add all the numbers together, and all the variables
24t+11=0
We move all terms containing t to the left, all other terms to the right
24t=-11
t=-11/24
t=-11/24

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