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2(t-1)-3(2t-1)=2-6(5t+3)
We move all terms to the left:
2(t-1)-3(2t-1)-(2-6(5t+3))=0
We multiply parentheses
2t-6t-(2-6(5t+3))-2+3=0
We calculate terms in parentheses: -(2-6(5t+3)), so:We add all the numbers together, and all the variables
2-6(5t+3)
determiningTheFunctionDomain -6(5t+3)+2
We multiply parentheses
-30t-18+2
We add all the numbers together, and all the variables
-30t-16
Back to the equation:
-(-30t-16)
-4t-(-30t-16)+1=0
We get rid of parentheses
-4t+30t+16+1=0
We add all the numbers together, and all the variables
26t+17=0
We move all terms containing t to the left, all other terms to the right
26t=-17
t=-17/26
t=-17/26
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