2(t-1)-5(2t-1)=16-7(3t+5)

Solution for 2(t-1)-5(2t-1)=16-7(3t+5) equation:

2(t-1)-5(2t-1)=16-7(3t+5)

We move all terms to the left:

2(t-1)-5(2t-1)-(16-7(3t+5))=0

We multiply parentheses

2t-10t-(16-7(3t+5))-2+5=0


We calculate terms in parentheses: -(16-7(3t+5)), so:

16-7(3t+5)

determiningTheFunctionDomain
-7(3t+5)+16

We multiply parentheses

-21t-35+16

We add all the numbers together, and all the variables

-21t-19

Back to the equation:

-(-21t-19)


We add all the numbers together, and all the variables

-8t-(-21t-19)+3=0

We get rid of parentheses

-8t+21t+19+3=0

We add all the numbers together, and all the variables

13t+22=0

We move all terms containing t to the left, all other terms to the right

13t=-22

t=-22/13

t=-1+9/13