2(t-2)+1=2-(t-4)

Solution for 2(t-2)+1=2-(t-4) equation:

2(t-2)+1=2-(t-4)

We move all terms to the left:

2(t-2)+1-(2-(t-4))=0

We multiply parentheses

2t-(2-(t-4))-4+1=0


We calculate terms in parentheses: -(2-(t-4)), so:

2-(t-4)

determiningTheFunctionDomain
-(t-4)+2

We get rid of parentheses

-t+4+2

We add all the numbers together, and all the variables

-1t+6

Back to the equation:

-(-1t+6)


We add all the numbers together, and all the variables

2t-(-1t+6)-3=0

We get rid of parentheses

2t+1t-6-3=0

We add all the numbers together, and all the variables

3t-9=0

We move all terms containing t to the left, all other terms to the right

3t=9

t=9/3

t=3