2(t-2)+1=2-(t-4)

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Solution for 2(t-2)+1=2-(t-4) equation:



2(t-2)+1=2-(t-4)
We move all terms to the left:
2(t-2)+1-(2-(t-4))=0
We multiply parentheses
2t-(2-(t-4))-4+1=0
We calculate terms in parentheses: -(2-(t-4)), so:
2-(t-4)
determiningTheFunctionDomain -(t-4)+2
We get rid of parentheses
-t+4+2
We add all the numbers together, and all the variables
-1t+6
Back to the equation:
-(-1t+6)
We add all the numbers together, and all the variables
2t-(-1t+6)-3=0
We get rid of parentheses
2t+1t-6-3=0
We add all the numbers together, and all the variables
3t-9=0
We move all terms containing t to the left, all other terms to the right
3t=9
t=9/3
t=3

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