2(t-2)+2=2(2t+-5)

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Solution for 2(t-2)+2=2(2t+-5) equation: 



2(t-2)+2=2(2t+-5)

We move all terms to the left:

2(t-2)+2-(2(2t+-5))=0

We add all the numbers together, and all the variables

2(t-2)-(2(2t-5))+2=0

We multiply parentheses

2t-(2(2t-5))-4+2=0



We calculate terms in parentheses: -(2(2t-5)), so:

2(2t-5)

We multiply parentheses

4t-10

Back to the equation:

-(4t-10)



We add all the numbers together, and all the variables

2t-(4t-10)-2=0

We get rid of parentheses

2t-4t+10-2=0

We add all the numbers together, and all the variables

-2t+8=0

We move all terms containing t to the left, all other terms to the right

-2t=-8

t=-8/-2

t=+4

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