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2(t-2)+2=2(2t-4)
We move all terms to the left:
2(t-2)+2-(2(2t-4))=0
We multiply parentheses
2t-(2(2t-4))-4+2=0
We calculate terms in parentheses: -(2(2t-4)), so:We add all the numbers together, and all the variables
2(2t-4)
We multiply parentheses
4t-8
Back to the equation:
-(4t-8)
2t-(4t-8)-2=0
We get rid of parentheses
2t-4t+8-2=0
We add all the numbers together, and all the variables
-2t+6=0
We move all terms containing t to the left, all other terms to the right
-2t=-6
t=-6/-2
t=+3
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