2(t-2)-3(4t+2)=30

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Solution for 2(t-2)-3(4t+2)=30 equation: 



2(t-2)-3(4t+2)=30

We move all terms to the left:

2(t-2)-3(4t+2)-(30)=0

We multiply parentheses

2t-12t-4-6-30=0

We add all the numbers together, and all the variables

-10t-40=0

We move all terms containing t to the left, all other terms to the right

-10t=40

t=40/-10

t=-4

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