2(t-2)=5(2-t)

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Solution for 2(t-2)=5(2-t) equation: 



2(t-2)=5(2-t)

We move all terms to the left:

2(t-2)-(5(2-t))=0

We add all the numbers together, and all the variables

2(t-2)-(5(-1t+2))=0

We multiply parentheses

2t-(5(-1t+2))-4=0



We calculate terms in parentheses: -(5(-1t+2)), so:

5(-1t+2)

We multiply parentheses

-5t+10

Back to the equation:

-(-5t+10)



We get rid of parentheses

2t+5t-10-4=0

We add all the numbers together, and all the variables

7t-14=0

We move all terms containing t to the left, all other terms to the right

7t=14

t=14/7

t=2

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