2(t-2)=5(t+3)

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Solution for 2(t-2)=5(t+3) equation: 



2(t-2)=5(t+3)

We move all terms to the left:

2(t-2)-(5(t+3))=0

We multiply parentheses

2t-(5(t+3))-4=0



We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)



We get rid of parentheses

2t-5t-15-4=0

We add all the numbers together, and all the variables

-3t-19=0

We move all terms containing t to the left, all other terms to the right

-3t=19

t=19/-3

t=-6+1/3

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