2(t-3)+3(t-2)=28

Solution for 2(t-3)+3(t-2)=28 equation:

Simplifying
2(t + -3) + 3(t + -2) = 28

Reorder the terms:
2(-3 + t) + 3(t + -2) = 28
(-3 * 2 + t * 2) + 3(t + -2) = 28
(-6 + 2t) + 3(t + -2) = 28

Reorder the terms:
-6 + 2t + 3(-2 + t) = 28
-6 + 2t + (-2 * 3 + t * 3) = 28
-6 + 2t + (-6 + 3t) = 28

Reorder the terms:
-6 + -6 + 2t + 3t = 28

Combine like terms: -6 + -6 = -12
-12 + 2t + 3t = 28

Combine like terms: 2t + 3t = 5t
-12 + 5t = 28

Solving
-12 + 5t = 28

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 5t = 28 + 12

Combine like terms: -12 + 12 = 0
0 + 5t = 28 + 12
5t = 28 + 12

Combine like terms: 28 + 12 = 40
5t = 40

Divide each side by '5'.
t = 8

Simplifying
t = 8