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2(t-3)+4=2(2t-3)
We move all terms to the left:
2(t-3)+4-(2(2t-3))=0
We multiply parentheses
2t-(2(2t-3))-6+4=0
We calculate terms in parentheses: -(2(2t-3)), so:We add all the numbers together, and all the variables
2(2t-3)
We multiply parentheses
4t-6
Back to the equation:
-(4t-6)
2t-(4t-6)-2=0
We get rid of parentheses
2t-4t+6-2=0
We add all the numbers together, and all the variables
-2t+4=0
We move all terms containing t to the left, all other terms to the right
-2t=-4
t=-4/-2
t=+2
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