2(t-3)+6=4(2t+5)-11

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Solution for 2(t-3)+6=4(2t+5)-11 equation: 



2(t-3)+6=4(2t+5)-11

We move all terms to the left:

2(t-3)+6-(4(2t+5)-11)=0

We multiply parentheses

2t-(4(2t+5)-11)-6+6=0



We calculate terms in parentheses: -(4(2t+5)-11), so:

4(2t+5)-11

We multiply parentheses

8t+20-11

We add all the numbers together, and all the variables

8t+9

Back to the equation:

-(8t+9)



We add all the numbers together, and all the variables

2t-(8t+9)=0

We get rid of parentheses

2t-8t-9=0

We add all the numbers together, and all the variables

-6t-9=0

We move all terms containing t to the left, all other terms to the right

-6t=9

t=9/-6

t=-1+1/2

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