2(t-3)-3(2t-5)=14-5(3t+2)

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Solution for 2(t-3)-3(2t-5)=14-5(3t+2) equation: 



2(t-3)-3(2t-5)=14-5(3t+2)

We move all terms to the left:

2(t-3)-3(2t-5)-(14-5(3t+2))=0

We multiply parentheses

2t-6t-(14-5(3t+2))-6+15=0



We calculate terms in parentheses: -(14-5(3t+2)), so:

14-5(3t+2)

determiningTheFunctionDomain
-5(3t+2)+14

We multiply parentheses

-15t-10+14

We add all the numbers together, and all the variables

-15t+4

Back to the equation:

-(-15t+4)



We add all the numbers together, and all the variables

-4t-(-15t+4)+9=0

We get rid of parentheses

-4t+15t-4+9=0

We add all the numbers together, and all the variables

11t+5=0

We move all terms containing t to the left, all other terms to the right

11t=-5

t=-5/11

t=-5/11

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