2(t-3)-5(2t+2)=4t

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Solution for 2(t-3)-5(2t+2)=4t equation: 



2(t-3)-5(2t+2)=4t

We move all terms to the left:

2(t-3)-5(2t+2)-(4t)=0

We add all the numbers together, and all the variables

-4t+2(t-3)-5(2t+2)=0

We multiply parentheses

-4t+2t-10t-6-10=0

We add all the numbers together, and all the variables

-12t-16=0

We move all terms containing t to the left, all other terms to the right

-12t=16

t=16/-12

t=-1+1/3

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