2(t-4)+4=2(2t-4)

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Solution for 2(t-4)+4=2(2t-4) equation: 



2(t-4)+4=2(2t-4)

We move all terms to the left:

2(t-4)+4-(2(2t-4))=0

We multiply parentheses

2t-(2(2t-4))-8+4=0



We calculate terms in parentheses: -(2(2t-4)), so:

2(2t-4)

We multiply parentheses

4t-8

Back to the equation:

-(4t-8)



We add all the numbers together, and all the variables

2t-(4t-8)-4=0

We get rid of parentheses

2t-4t+8-4=0

We add all the numbers together, and all the variables

-2t+4=0

We move all terms containing t to the left, all other terms to the right

-2t=-4

t=-4/-2

t=+2

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