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2(t-4)+4=2(t-6)
We move all terms to the left:
2(t-4)+4-(2(t-6))=0
We multiply parentheses
2t-(2(t-6))-8+4=0
We calculate terms in parentheses: -(2(t-6)), so:We add all the numbers together, and all the variables
2(t-6)
We multiply parentheses
2t-12
Back to the equation:
-(2t-12)
2t-(2t-12)-4=0
We get rid of parentheses
2t-2t+12-4=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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