2(t-4)=5(t-7)

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Solution for 2(t-4)=5(t-7) equation: 



2(t-4)=5(t-7)

We move all terms to the left:

2(t-4)-(5(t-7))=0

We multiply parentheses

2t-(5(t-7))-8=0



We calculate terms in parentheses: -(5(t-7)), so:

5(t-7)

We multiply parentheses

5t-35

Back to the equation:

-(5t-35)



We get rid of parentheses

2t-5t+35-8=0

We add all the numbers together, and all the variables

-3t+27=0

We move all terms containing t to the left, all other terms to the right

-3t=-27

t=-27/-3

t=+9

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