2(t-4)=6(3t+5)

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Solution for 2(t-4)=6(3t+5) equation: 



2(t-4)=6(3t+5)

We move all terms to the left:

2(t-4)-(6(3t+5))=0

We multiply parentheses

2t-(6(3t+5))-8=0



We calculate terms in parentheses: -(6(3t+5)), so:

6(3t+5)

We multiply parentheses

18t+30

Back to the equation:

-(18t+30)



We get rid of parentheses

2t-18t-30-8=0

We add all the numbers together, and all the variables

-16t-38=0

We move all terms containing t to the left, all other terms to the right

-16t=38

t=38/-16

t=-2+3/8

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