2(t-5)-3(2t=7)12-5(3+1)

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Solution for 2(t-5)-3(2t=7)12-5(3+1) equation: 



2(t-5)-3(2t=7)12-5(3+1)

We move all terms to the left:

2(t-5)-3(2t-(7)12-5(3+1))=0

We add all the numbers together, and all the variables

2(t-5)-3(2t-712-54)=0

We multiply parentheses

2t-6t-10+2136+162=0

We add all the numbers together, and all the variables

-4t+2288=0

We move all terms containing t to the left, all other terms to the right

-4t=-2288

t=-2288/-4

t=+572

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