2(t-5)=3(4+t)

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Solution for 2(t-5)=3(4+t) equation:



2(t-5)=3(4+t)
We move all terms to the left:
2(t-5)-(3(4+t))=0
We add all the numbers together, and all the variables
2(t-5)-(3(t+4))=0
We multiply parentheses
2t-(3(t+4))-10=0
We calculate terms in parentheses: -(3(t+4)), so:
3(t+4)
We multiply parentheses
3t+12
Back to the equation:
-(3t+12)
We get rid of parentheses
2t-3t-12-10=0
We add all the numbers together, and all the variables
-1t-22=0
We move all terms containing t to the left, all other terms to the right
-t=22
t=22/-1
t=-22

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