2(t-5)=3(4+t)

Solution for 2(t-5)=3(4+t) equation:

2(t-5)=3(4+t)

We move all terms to the left:

2(t-5)-(3(4+t))=0

We add all the numbers together, and all the variables

2(t-5)-(3(t+4))=0

We multiply parentheses

2t-(3(t+4))-10=0


We calculate terms in parentheses: -(3(t+4)), so:

3(t+4)

We multiply parentheses

3t+12

Back to the equation:

-(3t+12)


We get rid of parentheses

2t-3t-12-10=0

We add all the numbers together, and all the variables

-1t-22=0

We move all terms containing t to the left, all other terms to the right

-t=22

t=22/-1

t=-22