2(t-5)=3-(t+4)

Solution for 2(t-5)=3-(t+4) equation:

2(t-5)=3-(t+4)

We move all terms to the left:

2(t-5)-(3-(t+4))=0

We multiply parentheses

2t-(3-(t+4))-10=0


We calculate terms in parentheses: -(3-(t+4)), so:

3-(t+4)

determiningTheFunctionDomain
-(t+4)+3

We get rid of parentheses

-t-4+3

We add all the numbers together, and all the variables

-1t-1

Back to the equation:

-(-1t-1)


We get rid of parentheses

2t+1t+1-10=0

We add all the numbers together, and all the variables

3t-9=0

We move all terms containing t to the left, all other terms to the right

3t=9

t=9/3

t=3