2(t-7)+2(8t-8)=17(t-2)+10

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Solution for 2(t-7)+2(8t-8)=17(t-2)+10 equation: 



2(t-7)+2(8t-8)=17(t-2)+10

We move all terms to the left:

2(t-7)+2(8t-8)-(17(t-2)+10)=0

We multiply parentheses

2t+16t-(17(t-2)+10)-14-16=0



We calculate terms in parentheses: -(17(t-2)+10), so:

17(t-2)+10

We multiply parentheses

17t-34+10

We add all the numbers together, and all the variables

17t-24

Back to the equation:

-(17t-24)



We add all the numbers together, and all the variables

18t-(17t-24)-30=0

We get rid of parentheses

18t-17t+24-30=0

We add all the numbers together, and all the variables

t-6=0

We move all terms containing t to the left, all other terms to the right

t=6

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