2(u+)+4u=3(2u-1)+8

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Solution for 2(u+)+4u=3(2u-1)+8 equation:



2(u+)+4u=3(2u-1)+8
We move all terms to the left:
2(u+)+4u-(3(2u-1)+8)=0
We add all the numbers together, and all the variables
2(+u)+4u-(3(2u-1)+8)=0
We add all the numbers together, and all the variables
4u+2(+u)-(3(2u-1)+8)=0
We multiply parentheses
4u+2u-(3(2u-1)+8)=0
We calculate terms in parentheses: -(3(2u-1)+8), so:
3(2u-1)+8
We multiply parentheses
6u-3+8
We add all the numbers together, and all the variables
6u+5
Back to the equation:
-(6u+5)
We add all the numbers together, and all the variables
6u-(6u+5)=0
We get rid of parentheses
6u-6u-5=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation

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