2(u+)+4u=3(2u-1)=8

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Solution for 2(u+)+4u=3(2u-1)=8 equation: 



2(u+)+4u=3(2u-1)=8

We move all terms to the left:

2(u+)+4u-(3(2u-1))=0

We add all the numbers together, and all the variables

2(+u)+4u-(3(2u-1))=0

We add all the numbers together, and all the variables

4u+2(+u)-(3(2u-1))=0

We multiply parentheses

4u+2u-(3(2u-1))=0



We calculate terms in parentheses: -(3(2u-1)), so:

3(2u-1)

We multiply parentheses

6u-3

Back to the equation:

-(6u-3)



We add all the numbers together, and all the variables

6u-(6u-3)=0

We get rid of parentheses

6u-6u+3=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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