2(u+1)+4u=3(2u+1)+8

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Solution for 2(u+1)+4u=3(2u+1)+8 equation: 



2(u+1)+4u=3(2u+1)+8

We move all terms to the left:

2(u+1)+4u-(3(2u+1)+8)=0

We add all the numbers together, and all the variables

4u+2(u+1)-(3(2u+1)+8)=0

We multiply parentheses

4u+2u-(3(2u+1)+8)+2=0



We calculate terms in parentheses: -(3(2u+1)+8), so:

3(2u+1)+8

We multiply parentheses

6u+3+8

We add all the numbers together, and all the variables

6u+11

Back to the equation:

-(6u+11)



We add all the numbers together, and all the variables

6u-(6u+11)+2=0

We get rid of parentheses

6u-6u-11+2=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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