2(u+1)+4u=3(2u-1)+8

Solution for 2(u+1)+4u=3(2u-1)+8 equation:

Simplifying
2(u + 1) + 4u = 3(2u + -1) + 8

Reorder the terms:
2(1 + u) + 4u = 3(2u + -1) + 8
(1 * 2 + u * 2) + 4u = 3(2u + -1) + 8
(2 + 2u) + 4u = 3(2u + -1) + 8

Combine like terms: 2u + 4u = 6u
2 + 6u = 3(2u + -1) + 8

Reorder the terms:
2 + 6u = 3(-1 + 2u) + 8
2 + 6u = (-1 * 3 + 2u * 3) + 8
2 + 6u = (-3 + 6u) + 8

Reorder the terms:
2 + 6u = -3 + 8 + 6u

Combine like terms: -3 + 8 = 5
2 + 6u = 5 + 6u

Add '-6u' to each side of the equation.
2 + 6u + -6u = 5 + 6u + -6u

Combine like terms: 6u + -6u = 0
2 + 0 = 5 + 6u + -6u
2 = 5 + 6u + -6u

Combine like terms: 6u + -6u = 0
2 = 5 + 0
2 = 5

Solving
2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.