2(u+1)+4u=3(u-1)+7

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Solution for 2(u+1)+4u=3(u-1)+7 equation: 



2(u+1)+4u=3(u-1)+7

We move all terms to the left:

2(u+1)+4u-(3(u-1)+7)=0

We add all the numbers together, and all the variables

4u+2(u+1)-(3(u-1)+7)=0

We multiply parentheses

4u+2u-(3(u-1)+7)+2=0



We calculate terms in parentheses: -(3(u-1)+7), so:

3(u-1)+7

We multiply parentheses

3u-3+7

We add all the numbers together, and all the variables

3u+4

Back to the equation:

-(3u+4)



We add all the numbers together, and all the variables

6u-(3u+4)+2=0

We get rid of parentheses

6u-3u-4+2=0

We add all the numbers together, and all the variables

3u-2=0

We move all terms containing u to the left, all other terms to the right

3u=2

u=2/3

u=2/3

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