2(u+1)+7=3(u-2)+u

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Solution for 2(u+1)+7=3(u-2)+u equation: 



2(u+1)+7=3(u-2)+u

We move all terms to the left:

2(u+1)+7-(3(u-2)+u)=0

We multiply parentheses

2u-(3(u-2)+u)+2+7=0



We calculate terms in parentheses: -(3(u-2)+u), so:

3(u-2)+u

We add all the numbers together, and all the variables

u+3(u-2)

We multiply parentheses

u+3u-6

We add all the numbers together, and all the variables

4u-6

Back to the equation:

-(4u-6)



We add all the numbers together, and all the variables

2u-(4u-6)+9=0

We get rid of parentheses

2u-4u+6+9=0

We add all the numbers together, and all the variables

-2u+15=0

We move all terms containing u to the left, all other terms to the right

-2u=-15

u=-15/-2

u=7+1/2

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