2(u+2)+u=3(u-1)

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Solution for 2(u+2)+u=3(u-1) equation:


Simplifying
2(u + 2) + u = 3(u + -1)

Reorder the terms:
2(2 + u) + u = 3(u + -1)
(2 * 2 + u * 2) + u = 3(u + -1)
(4 + 2u) + u = 3(u + -1)

Combine like terms: 2u + u = 3u
4 + 3u = 3(u + -1)

Reorder the terms:
4 + 3u = 3(-1 + u)
4 + 3u = (-1 * 3 + u * 3)
4 + 3u = (-3 + 3u)

Add '-3u' to each side of the equation.
4 + 3u + -3u = -3 + 3u + -3u

Combine like terms: 3u + -3u = 0
4 + 0 = -3 + 3u + -3u
4 = -3 + 3u + -3u

Combine like terms: 3u + -3u = 0
4 = -3 + 0
4 = -3

Solving
4 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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