2(u+2)+u=3(u-1)+6

Solution for 2(u+2)+u=3(u-1)+6 equation:

Simplifying
2(u + 2) + u = 3(u + -1) + 6

Reorder the terms:
2(2 + u) + u = 3(u + -1) + 6
(2 * 2 + u * 2) + u = 3(u + -1) + 6
(4 + 2u) + u = 3(u + -1) + 6

Combine like terms: 2u + u = 3u
4 + 3u = 3(u + -1) + 6

Reorder the terms:
4 + 3u = 3(-1 + u) + 6
4 + 3u = (-1 * 3 + u * 3) + 6
4 + 3u = (-3 + 3u) + 6

Reorder the terms:
4 + 3u = -3 + 6 + 3u

Combine like terms: -3 + 6 = 3
4 + 3u = 3 + 3u

Add '-3u' to each side of the equation.
4 + 3u + -3u = 3 + 3u + -3u

Combine like terms: 3u + -3u = 0
4 + 0 = 3 + 3u + -3u
4 = 3 + 3u + -3u

Combine like terms: 3u + -3u = 0
4 = 3 + 0
4 = 3

Solving
4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.