2(u+3)+1=19

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Solution for 2(u+3)+1=19 equation: 



2(u+3)+1=19

We move all terms to the left:

2(u+3)+1-(19)=0

We add all the numbers together, and all the variables

2(u+3)-18=0

We multiply parentheses

2u+6-18=0

We add all the numbers together, and all the variables

2u-12=0

We move all terms containing u to the left, all other terms to the right

2u=12

u=12/2

u=6

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