2(u+3)=-4(4u-1)+6u

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Solution for 2(u+3)=-4(4u-1)+6u equation: 



2(u+3)=-4(4u-1)+6u

We move all terms to the left:

2(u+3)-(-4(4u-1)+6u)=0

We multiply parentheses

2u-(-4(4u-1)+6u)+6=0



We calculate terms in parentheses: -(-4(4u-1)+6u), so:

-4(4u-1)+6u

We add all the numbers together, and all the variables

6u-4(4u-1)

We multiply parentheses

6u-16u+4

We add all the numbers together, and all the variables

-10u+4

Back to the equation:

-(-10u+4)



We get rid of parentheses

2u+10u-4+6=0

We add all the numbers together, and all the variables

12u+2=0

We move all terms containing u to the left, all other terms to the right

12u=-2

u=-2/12

u=-1/6

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