2(u+3)=-6u-42

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Solution for 2(u+3)=-6u-42 equation: 



2(u+3)=-6u-42

We move all terms to the left:

2(u+3)-(-6u-42)=0

We multiply parentheses

2u-(-6u-42)+6=0

We get rid of parentheses

2u+6u+42+6=0

We add all the numbers together, and all the variables

8u+48=0

We move all terms containing u to the left, all other terms to the right

8u=-48

u=-48/8

u=-6

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