2(u+3)=3(1-u)+25

Solution for 2(u+3)=3(1-u)+25 equation:

2(u+3)=3(1-u)+25

We move all terms to the left:

2(u+3)-(3(1-u)+25)=0

We add all the numbers together, and all the variables

2(u+3)-(3(-1u+1)+25)=0

We multiply parentheses

2u-(3(-1u+1)+25)+6=0


We calculate terms in parentheses: -(3(-1u+1)+25), so:

3(-1u+1)+25

We multiply parentheses

-3u+3+25

We add all the numbers together, and all the variables

-3u+28

Back to the equation:

-(-3u+28)


We get rid of parentheses

2u+3u-28+6=0

We add all the numbers together, and all the variables

5u-22=0

We move all terms containing u to the left, all other terms to the right

5u=22

u=22/5

u=4+2/5