2(u+3)=7u-4

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Solution for 2(u+3)=7u-4 equation:



2(u+3)=7u-4
We move all terms to the left:
2(u+3)-(7u-4)=0
We multiply parentheses
2u-(7u-4)+6=0
We get rid of parentheses
2u-7u+4+6=0
We add all the numbers together, and all the variables
-5u+10=0
We move all terms containing u to the left, all other terms to the right
-5u=-10
u=-10/-5
u=+2

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