2(u+4)=-2(5u-8)+6u

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Solution for 2(u+4)=-2(5u-8)+6u equation: 



2(u+4)=-2(5u-8)+6u

We move all terms to the left:

2(u+4)-(-2(5u-8)+6u)=0

We multiply parentheses

2u-(-2(5u-8)+6u)+8=0



We calculate terms in parentheses: -(-2(5u-8)+6u), so:

-2(5u-8)+6u

We add all the numbers together, and all the variables

6u-2(5u-8)

We multiply parentheses

6u-10u+16

We add all the numbers together, and all the variables

-4u+16

Back to the equation:

-(-4u+16)



We get rid of parentheses

2u+4u-16+8=0

We add all the numbers together, and all the variables

6u-8=0

We move all terms containing u to the left, all other terms to the right

6u=8

u=8/6

u=1+1/3

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