2(u+4)=8u-28

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Solution for 2(u+4)=8u-28 equation:



2(u+4)=8u-28
We move all terms to the left:
2(u+4)-(8u-28)=0
We multiply parentheses
2u-(8u-28)+8=0
We get rid of parentheses
2u-8u+28+8=0
We add all the numbers together, and all the variables
-6u+36=0
We move all terms containing u to the left, all other terms to the right
-6u=-36
u=-36/-6
u=+6

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