2(u+5)=-4(2u-1)+u

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Solution for 2(u+5)=-4(2u-1)+u equation: 



2(u+5)=-4(2u-1)+u

We move all terms to the left:

2(u+5)-(-4(2u-1)+u)=0

We multiply parentheses

2u-(-4(2u-1)+u)+10=0



We calculate terms in parentheses: -(-4(2u-1)+u), so:

-4(2u-1)+u

We add all the numbers together, and all the variables

u-4(2u-1)

We multiply parentheses

u-8u+4

We add all the numbers together, and all the variables

-7u+4

Back to the equation:

-(-7u+4)



We get rid of parentheses

2u+7u-4+10=0

We add all the numbers together, and all the variables

9u+6=0

We move all terms containing u to the left, all other terms to the right

9u=-6

u=-6/9

u=-2/3

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