2(u-1)-2=-2(-8u+1)-8u

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Solution for 2(u-1)-2=-2(-8u+1)-8u equation: 



2(u-1)-2=-2(-8u+1)-8u

We move all terms to the left:

2(u-1)-2-(-2(-8u+1)-8u)=0

We multiply parentheses

2u-(-2(-8u+1)-8u)-2-2=0



We calculate terms in parentheses: -(-2(-8u+1)-8u), so:

-2(-8u+1)-8u

We add all the numbers together, and all the variables

-8u-2(-8u+1)

We multiply parentheses

-8u+16u-2

We add all the numbers together, and all the variables

8u-2

Back to the equation:

-(8u-2)



We add all the numbers together, and all the variables

2u-(8u-2)-4=0

We get rid of parentheses

2u-8u+2-4=0

We add all the numbers together, and all the variables

-6u-2=0

We move all terms containing u to the left, all other terms to the right

-6u=2

u=2/-6

u=-1/3

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