2(u-1)=5u+1-3(-3u-4)

Solution for 2(u-1)=5u+1-3(-3u-4) equation:

2(u-1)=5u+1-3(-3u-4)

We move all terms to the left:

2(u-1)-(5u+1-3(-3u-4))=0

We multiply parentheses

2u-(5u+1-3(-3u-4))-2=0


We calculate terms in parentheses: -(5u+1-3(-3u-4)), so:

5u+1-3(-3u-4)

determiningTheFunctionDomain
5u-3(-3u-4)+1

We multiply parentheses

5u+9u+12+1

We add all the numbers together, and all the variables

14u+13

Back to the equation:

-(14u+13)


We get rid of parentheses

2u-14u-13-2=0

We add all the numbers together, and all the variables

-12u-15=0

We move all terms containing u to the left, all other terms to the right

-12u=15

u=15/-12

u=-1+1/4