2(u-2)-2=-6(-3u+4)-4u

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Solution for 2(u-2)-2=-6(-3u+4)-4u equation: 



2(u-2)-2=-6(-3u+4)-4u

We move all terms to the left:

2(u-2)-2-(-6(-3u+4)-4u)=0

We multiply parentheses

2u-(-6(-3u+4)-4u)-4-2=0



We calculate terms in parentheses: -(-6(-3u+4)-4u), so:

-6(-3u+4)-4u

We add all the numbers together, and all the variables

-4u-6(-3u+4)

We multiply parentheses

-4u+18u-24

We add all the numbers together, and all the variables

14u-24

Back to the equation:

-(14u-24)



We add all the numbers together, and all the variables

2u-(14u-24)-6=0

We get rid of parentheses

2u-14u+24-6=0

We add all the numbers together, and all the variables

-12u+18=0

We move all terms containing u to the left, all other terms to the right

-12u=-18

u=-18/-12

u=1+1/2

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