2(u-2)=2u+8-3(-5u-2)

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Solution for 2(u-2)=2u+8-3(-5u-2) equation: 



2(u-2)=2u+8-3(-5u-2)

We move all terms to the left:

2(u-2)-(2u+8-3(-5u-2))=0

We multiply parentheses

2u-(2u+8-3(-5u-2))-4=0



We calculate terms in parentheses: -(2u+8-3(-5u-2)), so:

2u+8-3(-5u-2)

determiningTheFunctionDomain
2u-3(-5u-2)+8

We multiply parentheses

2u+15u+6+8

We add all the numbers together, and all the variables

17u+14

Back to the equation:

-(17u+14)



We get rid of parentheses

2u-17u-14-4=0

We add all the numbers together, and all the variables

-15u-18=0

We move all terms containing u to the left, all other terms to the right

-15u=18

u=18/-15

u=-1+1/5

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