2(u-2)=6u+6-2(-3u-1)

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Solution for 2(u-2)=6u+6-2(-3u-1) equation: 



2(u-2)=6u+6-2(-3u-1)

We move all terms to the left:

2(u-2)-(6u+6-2(-3u-1))=0

We multiply parentheses

2u-(6u+6-2(-3u-1))-4=0



We calculate terms in parentheses: -(6u+6-2(-3u-1)), so:

6u+6-2(-3u-1)

determiningTheFunctionDomain
6u-2(-3u-1)+6

We multiply parentheses

6u+6u+2+6

We add all the numbers together, and all the variables

12u+8

Back to the equation:

-(12u+8)



We get rid of parentheses

2u-12u-8-4=0

We add all the numbers together, and all the variables

-10u-12=0

We move all terms containing u to the left, all other terms to the right

-10u=12

u=12/-10

u=-1+1/5

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